substituting a = -2 in a^2 - 3a + 4 gives 6
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(-2)^2 - 3(-2) + 4
=> 4 + 6 + 4
=> 14
Answered by
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Step-by-step explanation:
a²-3a+4=6
-2²-3(-2)+4
-4-6+4
both 4are cancel so 6 is remain
mark breinliest
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