Question

substituting a=(-2) in a^2-3a+6 gives 6​

Answer 1

Answer:

a = -2

${a}^{2} - 3a + 6 \\ = { - 2}^{2} + ( - 3 \times - 2) + 6 \\ = 4 + 6 + 6 \\ = 10 + 6 = 16$

Answer 2

question :

${a}^{2} - 3a + 6$

given :

a = -2

${a}^{2} - 3a + 6 \\ \\ = { - 2}^{2} - 3( - 2) + 6 \\ \\ = 4 + 6 + 6 \\ \\ = 16$

16 is the answer