Substitution method : 4x+y=34
3x-2y=20
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Answered by
2
Hey there!
3x-2y=20 .... equation (1)
4x+y =34.... equation (2)
y=34-4x
Substituting in first equation
3x -2( 34-4x) =20
3x - 68 +8x=20
(3+8)x-68=20
11x-68=20
11x=20+68
11x=88
x=88/11 =8
Now y=34-4x
y=34-4(8)
y=34-32
y=2
(x,y) =(8,2)
hope helped!
3x-2y=20 .... equation (1)
4x+y =34.... equation (2)
y=34-4x
Substituting in first equation
3x -2( 34-4x) =20
3x - 68 +8x=20
(3+8)x-68=20
11x-68=20
11x=20+68
11x=88
x=88/11 =8
Now y=34-4x
y=34-4(8)
y=34-32
y=2
(x,y) =(8,2)
hope helped!
chaudharipriyanka:
Thanks
Answered by
1
Hi there !!
4x + y = 34
y = 34-4x
substitute this value in the equation :-
3x-2y=20
3x - 2 [ 34-4x ] = 20
3x - 68 + 8x = 20
11x - 68 = 20
11x = 88
x = 88/11
x = 8
we have got the value of one variable :- "x"
put this value in any one of the equations :-
3x - 2y=20
24 - 2y = 20
-2y = 20 - 24
-2y = -4
y = 2
Hope this Helps You !!
4x + y = 34
y = 34-4x
substitute this value in the equation :-
3x-2y=20
3x - 2 [ 34-4x ] = 20
3x - 68 + 8x = 20
11x - 68 = 20
11x = 88
x = 88/11
x = 8
we have got the value of one variable :- "x"
put this value in any one of the equations :-
3x - 2y=20
24 - 2y = 20
-2y = 20 - 24
-2y = -4
y = 2
Hope this Helps You !!
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