substitution method in 0.3x+0.4y=2.5 and 0.5x-0.3y=0.3
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Answer:
0.3x+0.4y=2.5-----(1)
0.5x0.3y=0.3-------(2)
Multiplying both the equations by 10,
3x+4y=25-----(3)
5x-3y=3-----(4)
Again Multiplying (3) by 5 and (4) by 3,
15x+20y=125------(5)
15x-9y=9------(6)
Subtracting (6) from (5),
29y=116
y=4
Substituting this value of y in (6),
15x-9(4)=9
15x-36+9
15x=45
x=3
Answers:
↪x=3
↪y=4
hope it helps
tq............/////////////
Step-by-step explanation:
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