Substitution method, linear equations, 3x-y=3 9x-3y=9
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Answered by
2
Answer:
3x-y = 3.....(1)
9x-3y = 9.....(2)
now, using substitution method
eq(1)
3x-y = 3
3x = 3+y
x = (3+y)/3
Replacing x in eq(2)
9(3+y)/3-3y = 9
3(3+y)-3y = 9
9+3y-3y = 9
9 = 9
Answered by
44
HERE IS YOUR ANSWER MATE.....;
(i) Given,
x + y = 14 and x – y = 4 are the two equations.
From 1st equation, we get,
x = 14 – y
Now, put the value of x in second equation to get,
(14 – y) – y = 4
14 – 2y = 4
2y = 10
Or y = 5
By the value of y, we can now find the value of x;
∵ x = 14 – y
∴ x = 14 – 5
Or x = 9
Hence, x = 9 and y = 5.
(ii) Given,
3x – y = 3 and 9x – 3y = 9 are the two equations.
From 1st equation, we get,
x = (3 + y)/3
Now, substitute the value of x in the given second equation to get,
9[(3 + y)/3] – 3y = 9
⇒ 3(3+y) – 3y = 9
⇒ 9 + 3y – 3y = 9
⇒ 9 = 9
Therefore, y has infinite values and since, x = (3 + y)/3, so x also has infinite values.
Hope it's Helpful....:)
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