substitution method se banao 2x-y=4 & 3y-x=3
Answers
Answered by
2
make y the subject of both eqns, we get,
y=2x-4 and y=(3+x)/3
equating both eqns now,
2x-4=(3+x)/3
6x-12=3+x
5x=15
x=3
substituting the value of x in first equation
2(3)-y=4
6-y=4
y=2
hope this helps!!
y=2x-4 and y=(3+x)/3
equating both eqns now,
2x-4=(3+x)/3
6x-12=3+x
5x=15
x=3
substituting the value of x in first equation
2(3)-y=4
6-y=4
y=2
hope this helps!!
hitarthgodhani:
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Answered by
2
Hey!!!...here is ur answer
by substitution method
2x-y=4
y=2x-4
substitute the value of y in 3y-x=3
3 (2x-4)-x=3
6x-12-x=3
5x=15
x=3
put x=3 in 2x-y=4
2×3-y=4
y=2
So the value of x=3 and y=2
Hope it will help you
by substitution method
2x-y=4
y=2x-4
substitute the value of y in 3y-x=3
3 (2x-4)-x=3
6x-12-x=3
5x=15
x=3
put x=3 in 2x-y=4
2×3-y=4
y=2
So the value of x=3 and y=2
Hope it will help you
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