Substitution method solve the equation 3x-2y=5 2x+y=7
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Answered by
0
3x=5+2y
x=5+2y/3
2*5+2y/3+y=7
10+4y/3+y=7
10+4y+3y/3=7
10+7y=21
7y=11
y=11/7
therefore
x=5+2y/3
x=5+2×11÷7/3
x=35+66/7
x=101/7
x=5+2y/3
2*5+2y/3+y=7
10+4y/3+y=7
10+4y+3y/3=7
10+7y=21
7y=11
y=11/7
therefore
x=5+2y/3
x=5+2×11÷7/3
x=35+66/7
x=101/7
Answered by
1
Answer:-
Step by step explanation
3x - 2y = 5 ------ ( 1 )
2x + y = 7 -------( 2 )
From eq'n ( 1 )
3x - 2y = 5
=> 3x = 2y + 5
=> x = (2y + 5 / 3 ) ------- ( 3 )
Substitute eq'n ( 3 ) in eq'n ( 2 )
2x + y = 7
=> 2 (2y + 5 / 3 ) + y = 7
=> ( 4y + 10 / 3 ) + y = 7
=> 4y + 10 + 3y = 30
=> 7y = 30 - 10
=> 7y = 20
=> y = 20 / 7
From eq'n ( 1 )
3x - 2y = 5
=> 3x - 2 ( 20 / 7 ) = 5
=> 3x - 40 / 7 = 5
=> 21x - 40 = 35
=> 21x = 35 + 40
=> 21x = 75
=> x = 75 / 21
=> x = 25 / 7
Therefore, the value of x is 25 / 7 and y is 20 / 7.
Hope it helps!
Step by step explanation
3x - 2y = 5 ------ ( 1 )
2x + y = 7 -------( 2 )
From eq'n ( 1 )
3x - 2y = 5
=> 3x = 2y + 5
=> x = (2y + 5 / 3 ) ------- ( 3 )
Substitute eq'n ( 3 ) in eq'n ( 2 )
2x + y = 7
=> 2 (2y + 5 / 3 ) + y = 7
=> ( 4y + 10 / 3 ) + y = 7
=> 4y + 10 + 3y = 30
=> 7y = 30 - 10
=> 7y = 20
=> y = 20 / 7
From eq'n ( 1 )
3x - 2y = 5
=> 3x - 2 ( 20 / 7 ) = 5
=> 3x - 40 / 7 = 5
=> 21x - 40 = 35
=> 21x = 35 + 40
=> 21x = 75
=> x = 75 / 21
=> x = 25 / 7
Therefore, the value of x is 25 / 7 and y is 20 / 7.
Hope it helps!
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