substract 3a ( a+b+c ) - 2a ( b-b+c ) from 4 a( c+b-c )
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Step-by-step explanation:
4c(−a+b+c)−[3a(a+b+c)−2b(a−b+c)]
4c(−a+b+c)−[3a2+3ab+3ac−2ab+2b2−2bc]
4c(−a+b+c)−[3a2+2b2+ab+3ac−2bc]
−4ac+4bc+4c2−3a2−2b2−ab−3ac+2bc
4c2−3a2−2b2−ab+6bc−7ac
Answered by
0
Answer:
3a(a+b+c)-2a(b+b+b)-4a(c+b+c)
3a²+3ab+3ac-2ab+2ab-2ac-4ac-4ab-4ac
3a²+3ab-4ab+3ac-10ac
3a²-ab-7ac
Step-by-step explanation:
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