Substract 4a^ 3 -3a^ 2 b+ab^ 2 -b^ 2 from a ^ 2 + b ^ 2 - 3a ^ 2 ^ b + 7a ^b ^ 2
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Answer:
a
2
+b
2
+4a+2b+5=0
⇒a
2
+4a+4+b
2
+2b+1=0
⇒(a+2)
2
+(b+1)
2
=0
a,b∈R
⇒a=−2,b=−1
a
2
+b
2
a
2
−b
2
=
4+1
4−1
=
5
3
.
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