substract r^2+p^2+p from q^2+r^2+p
please answer fast and with explanation
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Answer:
We need to factorise (p
2
−2pq+q
2
)−r
2
We have (p
2
−2pq+q
2
)−r
2
=(p−q)
2
−r
2
By using (a
2
−b
2
)=(a−b)(a+b)
Here a=(p−q),b=r
Therefore, (p
2
−2pq+q
2
)−r
2
=(p−q−r)(p−q+r)
Hence, factors are (p−q−r)(p−q+r).
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