Math, asked by ddibakarsarma, 5 months ago

substract the additive inverse of -7/-16 from 1whole of 19/20

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Answered by vivekgakkhar0710

Answer:

$1 \times \frac{19}{20} - ( \frac{ - 7}{16}) \: \: (additive \: inverse \: of \: - 7 \div - 16 \: is \: - 7 \div 16) \\ \frac{19}{20} + \frac{7}{16} \\ \frac{76 + 35}{80} \\ \frac{111}{80}$

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answer fastttt.........help guys...

substract the additive inverse of -7/-16 from 1whole of 19/20​

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substract the additive inverse of -7/-16 from 1whole of 19/20