substract the sum of -5/6 and 4/5 from the sum of -3/5 and 7/15.
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ples do the sum correcty
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\huge\bold{\red{Solution}} < /p > < p >Solution</p><p>
Let us first do the summation -
1) \: \dfrac{4}{5} + \: \dfrac{( - 5)}{9}1)
5
4
+
9
(−5)
\dfrac{4 \times 9 + ( - 5) \times 5}{45}
45
4×9+(−5)×5
\dfrac{36 - 25}{45}
45
36−25
\dfrac{11}{45}
45
11
Now,
Now, We can reduce -35/45 in simplest form i.e. -7/9
2) \: \dfrac{ ( - 7)}{15} \: + \: \dfrac{( - 7)}{9}2)
15
(−7)
+
9
(−7)
\dfrac{( - 7) \times 3 + ( - 7) \times 5}{45}
45
(−7)×3+(−7)×5
\dfrac{( - 21) - 35}{45}
45
(−21)−35
\dfrac{( - 56)}{45}
45
(−56)
NOW, LET US DO THE SUBTRACTION PART-
\dfrac{( - 56)}{45} - \dfrac{11}{45}
45
(−56)
−
45
11
\dfrac{ - 56 - 11}{45}
45
−56−11
FinalAnswer: \dfrac{ - 67}{45}
45
−67
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