Question

Substracting 19 from a number the number is 1 more than 1/3 of the number. Find the number​

Answer 1

Answer:

Let x be the number

Therefore, one=third of the number is

3

On subtraction of 1, we get

3

x

−1

⇒

3

x

−1=1

⇒

3

x

=2

⇒ x=2×3

⇒ x=6

Therefore, the required numbers is 6

Answer 2

Step-by-step explanation:

$let \: x \:be \: the \: number$

$therefore \: one \: third \: of \: the \: number \: \\ is \: \frac{x}{3}$

$on \: subtraction \: of \: 1 \: we \: get \: \frac{x}{3} - 1$

$= > \frac{x}{3} - 1 = 1$

$\frac{x}{3} = 2$

$x = 2 \times 3$

$x = 6$

Therefore the required number is 6

$\huge{ son \: prodigal}$