Math, asked by tanveerkaur926, 16 hours ago

subtarct 4a² + 3a²b + ab² + b ³ from a³ + b³ + 3a²b + 7ab²​

Answers

Answered by RownakSk
0

Answer:

a³+b³+4a²+6a²b+8ab²+b³

Answered by riddhi1302
1

Here's your answer...hope it helps!

(a^{3} +b^{3} +3a^{2} b+7ab^{2} )-(4a^{2} +3a^{2} b+ab^{2} +b^{3} )

=(a^{3} +b^{3} +3a^{2} b+7ab^{2} )-4a^{2} -3a^{2} b-ab^{2} -b^{3}

Grouping like terms together.

= a^{3}-4a^{2} +b^{3}-b^{3}+3a^{2} b-3a^{2} b+7ab^{2} -ab^{2}

= a^{3} -4a^{2}+6ab^{2}

Similar questions