Subtrach 4a-7ab+3b+12a-four 9ab+5b-3
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Answered by
21
Answer:
subtract 4a−7ab+3b+12 from 12a−9ab+5b−3
=12a−9ab+5b−3−(4a−7ab+3b+12)
=12a−9ab+5b−3−4a+7ab−3b−12
=8a−2ab+2b−15
Answered by
2
Answer:
4a+12a-7ab+9ab+3b+5b-3-4
=16a+2ab+8b-7
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