Subtract 10a - 6ab +7b + 12 from 12a -9ab +5b -3
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phase of a particle in SHM at time t is
137
6
The following inference is drawn from this
(A) the particle is at x = a/2 and moving in + X-direction
(B) the particle is at x = a/2 and moving in - X-direction
(C) the particle is at x = -a/2 and moving in + X-direction
(D) the particle is at x = -a/2 and moving in-X-direction
Super Position in SAK
Step-by-step explanation:
Subtract 10a - 6ab +7b + 12 from 12a -9ab +5b -3
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