Question

Subtract 16 x—11y+2z from the sum of 7x + 6 y + z and —9x + 3y —2z.
Explain step by step​

Answer 1

Step-by-step explanation:

◆7x + 6 y + z +( —9x + 3y —2z.)

Like terms together

7x—9x+ 6 y+ 3y +z—2z

●-2x+9y-z

subtract

◆ 16 x—11y+2z-2x+9y-z

Like terms together

16x-2x—11y+9y+2z-z

●14x-2y+z

Answer is 14x-2y+z .

Mark as brainiest answer.

Answer 2

Answer:

−9x+20y−3z−9 is the answer.

Step-by-step explanation:

$\bold\red{Question \: Given \: -}$

→ Subtract 16 x—11y+2z from the sum of 7x + 6 y + z and —9x + 3y —2z.

$\bold\blue{To \: Find \: -}$

→ The Difference of 16 x—11y+2z from the sum of 7x + 6 y + z and —9x + 3y —2z.

$\bold\orange{Solution \: -}$

→ The given expressions are 16x−11y+2z,7x+6y+z and −9+3y−2z

→ The given expressions are 16x−11y+2z,7x+6y+z and −9+3y−2zLet's perform the given operations:

→ The given expressions are 16x−11y+2z,7x+6y+z and −9+3y−2zLet's perform the given operations:Sum of 7x+6y+z and −9+3y−2z

→ The given expressions are 16x−11y+2z,7x+6y+z and −9+3y−2zLet's perform the given operations:Sum of 7x+6y+z and −9+3y−2z⇒7x+6y+z−9+3y−2z=7x+9y−z−9

→ The given expressions are 16x−11y+2z,7x+6y+z and −9+3y−2zLet's perform the given operations:Sum of 7x+6y+z and −9+3y−2z⇒7x+6y+z−9+3y−2z=7x+9y−z−9Now, subtracting 16x−11y+2z from 7x+9y−z−9

→ The given expressions are 16x−11y+2z,7x+6y+z and −9+3y−2zLet's perform the given operations:Sum of 7x+6y+z and −9+3y−2z⇒7x+6y+z−9+3y−2z=7x+9y−z−9Now, subtracting 16x−11y+2z from 7x+9y−z−9⇒7x+9y−z−9−(16x−11y+2z)

→ The given expressions are 16x−11y+2z,7x+6y+z and −9+3y−2zLet's perform the given operations:Sum of 7x+6y+z and −9+3y−2z⇒7x+6y+z−9+3y−2z=7x+9y−z−9Now, subtracting 16x−11y+2z from 7x+9y−z−9⇒7x+9y−z−9−(16x−11y+2z)⇒7x+9y−z−9−16x+11y−2z

→ The given expressions are 16x−11y+2z,7x+6y+z and −9+3y−2zLet's perform the given operations:Sum of 7x+6y+z and −9+3y−2z⇒7x+6y+z−9+3y−2z=7x+9y−z−9Now, subtracting 16x−11y+2z from 7x+9y−z−9⇒7x+9y−z−9−(16x−11y+2z)⇒7x+9y−z−9−16x+11y−2z⇒−9x+20y−3z−9

→ The given expressions are 16x−11y+2z,7x+6y+z and −9+3y−2zLet's perform the given operations:Sum of 7x+6y+z and −9+3y−2z⇒7x+6y+z−9+3y−2z=7x+9y−z−9Now, subtracting 16x−11y+2z from 7x+9y−z−9⇒7x+9y−z−9−(16x−11y+2z)⇒7x+9y−z−9−16x+11y−2z⇒−9x+20y−3z−9Hence, −9x+20y−3z−9 is the answer.

$\bold\green{Final \: Answer \: -}$

→ −9x+20y−3z−9 is the answer.

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