subtract 16xy-2-3bsquare+25xsuare from 4asquare+13xy-6csquare-1
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3xy-3-3bsquare-25xsquare-4asquare+6csquare
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Solution :
Let A = 16xy - 2 - 3b² +25x²
B = 5a² + 13x -6c² - 1
According to the problem given,
B - A
= 4a²+13xy-6c²+1
-(16xy²-2-3b²+25x²+1)
= 4a²+13xy-6c²+1-16xy²+2+3b²
-25x² - 1
= 4a² +3b² -6c² -25x²
-16xy²+13xy+2
••••
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