Math, asked by radhavyas, 1 year ago

subtract 16xy-2-3bsquare+25xsuare from 4asquare+13xy-6csquare-1​

Answers

Answered by aditya4589
1

3xy-3-3bsquare-25xsquare-4asquare+6csquare

Answered by mysticd
0

Solution :

Let A = 16xy - 2 - 3b² +25x²

B = 5a² + 13x -6c² - 1

According to the problem given,

B - A

= 4a²+13xy-6c²+1

-(16xy²-2-3b²+25x²+1)

= 4a²+13xy-6c²+1-16xy²+2+3b²

-25x² - 1

= 4a² +3b² -6c² -25x²

-16xy²+13xy+2

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