Question

subtract (19p+17p-7) from the sum of (-15p2+12p+4) and (-5p -14p-11)
Please do it! whoever does i will mark them as brainliest.

Answer 1

Step-by-step explanation:

(-15p²+12p+4)+(-5p²-14p-11)-(19p²+17p-7)

-15p²-5p²+12p-14p+4-11-19p²-17p+7

-20p²-2p-7-19p²-17p+7

-39p²-19p

Answer 2

$\huge\bold{\gray{\sf{Answer:}}}$

Explanation:

Concept:-

• $\bold{+\:-\:=\:-}$
• $\bold{-\:-=\:+(but\:sign\:of\:-)}$

Solving procedure:-

• Take like terms together and constant term one side it makes our calculation more easier.

Sum:

$= > - 15 {p}^{2} + 12p + 4 + ( - 5{p}^2) - 14p - 11$

$= > - 15 {p}^{2} + 12p + 4 - 5{p}^{2} - 14p - 11$

$= > - 15 {p}^{2} - 5{p}^{2} - 2p -7$

$= > - 20{p}^{2} - 2p -7$

substract $\bold{(19{p}^{2}+17p-7) }$from $\bold{ - 20 {p}^{2} - 2p -7}$

$= > - 20{p}^{2} - 2p -7 - (19{p}^{2}+ 17p - 7)$

$= > - 20 {p}^{2} - 2p -7- 19{p}^{2}- 17p + 7$

$= > - 39 {p}^{2} - 19p$

$\bold\fcolorbox{aqua}{orange}{Answer}$$\bold{ - 39 {p}^{2} - 19p }$