Question

Subtract 2/3y²-2/7y² from 1/3y²+5/7y²+y-2​

Answer 1

Answer:

(2x^2 + 3y^2 =6) x 3

(3x^2 + 2y^2 =6) x 2 multiplying both sides of equations 1 and 2

6x^2 + 9y^2 = 18

6x^2 + 4y^2 = 12

Subtracting equation 3 -4,

0 + 5y^2 = 6

Y^2 = 6/5

Y= / 6/5 square root

2x^2 + 2×6/5 = 6

4x^2+12 / 5 = 6

4x^2 +12 = 30

4x^2 = 18

X^2 = 18/4

X =root 18/4 ~ root 18 /2;