subtract (2/7-5/21) from the sum of 3/4 ,5/7 7/12
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Answer: Step-by-step explanation: (3/4 + 5/7 + 7/12) - (2/7 - 5/21). First we have to take out the LCM of the denominators 4, ...
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Step-by-step explanation:
First we add 3/4+5/7+7/12
Then,. (We use simple process of fraction addition)
- We take L.C.M of 4,7,12
- We get 84 as L.C.M,
- Divide 84 by 4
- We get 21 then
- Multiply with 3
- We get 63
- Again, divide 84 by 7
- We get 12
- Multiply it with 5
- We get 60
- Again, divide 84 by 12
- We get 7
- Multiply it by 7
- We get 49
- Now, add 63+60+49
- We get 172
- Divide it with 84
- We get 43/21
# Now solve, 2/7-5/21
- We use simple process of fraction substraction
Again, first solve for L.C.M of 7,21
- We get 21
- Divide 21 by 7
- We get 3
- Multiply it by 2
- We get 6
- Again, Divide 21 by 21
- We get 1
- Multiply it by 5
- We get 5
- Now Substract 5 from 6
- We get 1
- Divide it by 21
- We get 1/21
Now,substract 1/21. from 43/21
Again,we use the simple process of fraction substraction.
- Again,solve for L.C.M of 21 and 21
We get 21 as L.C.M
- Divide 21 by 21
- We get 1
- Multiply it by 43
- Again, Divide 21 by 21
- We get 1
- Multiply it by 1
- Now, substract 1 from 43
- We get 42
- Divide it by 21
- We get 2
Here, 2 is the answer.
Thank you.
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