subtract 2 ab + cd - ac - 2bd from ab - 2cd + 2ac + bd in column method
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2ab+cd−ac−2bd from ab−2cd+2ac+bd
The value of the subtraction is calculated as follows
(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)
=ab−2ab−2cd−cd+2ac+ac+bd+2bd
On calculating further, we get
=−ab−3cd+3ac+3bd
Answered by
2
Answer:
2ab+cd−ac−2bd from ab−2cd+2ac+bd
The value of the subtraction is calculated as follows
(ab−2cd+2ac+bd)−(2ab+cd−ac−2bd)
=ab−2ab−2cd−cd+2ac+ac+bd+2bd
On calculating further, we get
=−ab−3cd+3ac+3bd
I hope this answer will helps..
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