subtract 2(y^3-4y^2+5) from 4y(3y^2+5y-7)
Answers
Answered by
7
Hey! your answer-
= 4y(3y²+20y-7) - 2(y³-4y²+5)
= 12y³+20y²-28y - 2y³+8y²-10
= 12y³-2y³+20y²+8y²-28u-10
= 10y³+28y²-28y-10
Thus, the answer is-
10y³ + 28y² - 28y -10
Answered by
2
Answer:
Hey! your answer-
= 4y(3y²+20y-7) - 2(y³-4y²+5)
= 12y³+20y²-28y - 2y³+8y²-10
= 12y³-2y³+20y²+8y²-28u-10
= 10y³+28y²-28y-10
Thus, the answer is-
10y³+28y²-28y-10
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