Subtract 2×-y+z from 3×-2y-z to get
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So we should subtract the equation 2 with 1
3x-2y-z-[2x-y+z]
3x-2y+z-2x+y-z
3x-2x -2y+y +z-z
x-y should be subtracted
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Answer:
3x+2y-z
Step-by-step explanation:
(3x – y + z) + (x + y – 3z) – (x – 2y – z)
= 3x – y + z + x + y – 3z – x + 2y + z
= 3x + x – x – y + y + 2y + z + z – 3z
= 3x + 2y – z
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