Question

subtract 20-3x+4x^2-x^3 from x^3-x^2+2x-19​

Answer 1

Answer:

$\huge{\mathfrak{\purple{Answer}}}$

• Given - subtract 20-3x+4x^2-x^3 from x^3-x^2+2x-19

• To find - answer of this

• Solution

x^3 - x^2 + 2x - 19 - ( 20- 3x + 4x^2 - x^3)

x^3 - x^2 + 2x - 19 - 20 + 3x - 4x^2 + x^3

x^3 + x^3 - x^2 - 4x^2 + 2x + 3x - 19 - 20

2x^3 - 5x^2 + 5x - 29

# Be brainly

Answer 2

Question :

$\sf{ Subtract \: 20 - 3x + {4x}^{2} - {x}^{3}\:from\: {x}^{3} - {x}^{2} + 2x - 19}$

Answer :

$\implies\sf{ {x}^{3} - {x}^{2} + 2x - 19 - (20 - 3x + {4x}^{2} - {x}^{3}) }$

Changing the signs

$\implies\sf{ {x}^{3 } - {x}^{2} + 2x - 19 - 20 + 3x - {4x}^{2} + {x}^{3} }$

Arranging like terms together

$\implies\sf{ {x}^{3} + {x}^{3} - {x}^{2} - {4x}^{2} + 2x + 3x - 19 - 20 }$

$\implies\boxed {\sf{ {2x}^{3} - {5x}^{2} + 5x - 39}}\orange\bigstar$