Question

Subtract 21/4from the sum of 7/2 and 8/3​

Answer 1

Answer:

I don't know bro sorry bro I

Answer 2

Given: The numbers are$21/4, 7/2, and 8/3$.

We have to subtract$21/4$ from the sum of$7/2 \ and\ 8/3$.

By using the Bodmas rule, we are solving the above equation.

As we know that the Bodmas rule is used to remember the order of operations to be followed while solving expressions in mathematics.

Where,

$\begin{array}{l}\mathrm{B}=\text{brackets}\\\mathrm{O}=\text { order of powers or rules } \\\mathrm{D}=\text { division } \\\mathrm{M}=\text { multiplication } \\\mathrm{A}=\text { addition } \\\mathrm{S}=\text { subtraction }\end{array}$

We are solving in the following way:

We have,

The numbers are$21/4, 7/2, and 8/3$

The sum of$7/2 \ and\ 8/3$ will be:

$\Rightarrow \frac{7}{2} +\frac{8}{3} \\\\\Rightarrow \frac{37}{6}$

Now, subtracting$21/4$ from the sum of$7/2 \ and\ 8/3$:

$\Rightarrow \frac{37}{6} -\frac{21}{4} \\\\\Rightarrow \frac{11}{12}$

Hence, after subtracting$21/4$ from the sum of$7/2 \ and\ 8/3$ we get$\frac{11}{12}$.