Question

Subtract (2a-36+4 c) From the sum of
(a + 3b-4c) and (4a-b+9c).​

Answer 1

Answer:

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).

So, First we will do the sum of the three given polynomials,

Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)

=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)

=4a+8c

Now, we can perform the subtraction,

∴ Required difference

=(4a+8c)−(2a−3b+4c)

=4a+8c−2a+3b−4c

=2a+3b+4c

Answer 2

Answer:

3a +5b +c

Step-by-step explanation:

first do the sum of 2 given numbers as

(a+3b-4c ) + (4a-b+9c)

open the bracket

a+3b-4c +4a-b +9c

5a +2b+5c

now , subtract (2a-3b+4c) from 5a+2b+5c

so the form will be

5a+2b+5c -(2a-3b+4c)

5a+2b+5c -2a+3b-4c

3a +5b +c

therefore the answer is 3a+5b+c

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