Question

Subtract 2a’ – 3a² + 5a + 5 from 5a' + a² + 2a-3​

Answer 1

Explanation:

5a³+a²+2a-3-2a³+3a²-5a-5=0

3a³+4a²-3a-8=0

Answer 2

$\huge \underline\textbf{AnsWer}$

${2a} - {3a}^{2} + 5a + 5 \: from \: {5a} + {a}^{2} + 2a - 3$

$= {5a} + {a}^{2} + 2a - 3 - ( {2a} - {3a}^{2} + 5a + 5)$

$= 5a + {a}^{2} + 2a - 3 - 2a + {3a}^{2} - 5a + 5$

$= 5a + 2a - 5a + {a}^{2} + {3a}^{2} - 3 + 5$

$= 2a + {2a}^{2} + 2$

hope it helps u...!!