Question

Subtract 2a+3b-4c from the Sum
of 5a-20b+30 and 20+3b-4c
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Answer 1

Answer:

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Step-by-step explanation:

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).

So, First we will do the sum of the three given polynomials,

Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)

=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)

=4a+8c

Now, we can perform the subtraction,

∴  Required difference

=(4a+8c)−(2a−3b+4c)

=4a+8c−2a+3b−4c

=2a+3b+4c

Answer 2

5a-20b + 30-( 2a+3b-4c)

5a-20b+30-2a-3b+4c

5a-20a-2b-3b+4c+30

3a-25b-+4c+ 30

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