Question

Subtract (2a - 3b + 4c) from the sum of (a + 3b - 40), (4a - b +9c) and (-2b + 3c - a).​

Answer 1

QUESTION:-Subtract (2a - 3b + 4c) from the sum of (a + 3b - 40), (4a - b +9c) and (-2b + 3c - a)

ANSWER:-

$(a + 3b - 40 + 4a - b + 9c - 2b + 3c - a) - (2a - 3b + 4c)$

$a + 4a - a + 3b - b - 2b + 9c + 3c - 40 - (2a - 3b + 4c)$

$(4a + 3b - 3b + 12c - 40)- (2a - 3b + 4c)$

$(4a + 12c - 40)- (2a - 3b + 4c)$

$4a + 12c - 40- 2a + 3b - 4c$

$4a - 2a + 12c - 4c + 3b - 40$

$2a +3b + 8c - 40$

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