subtract (2a - 3b + 4c) from the sum of ( a + 3b - 4c), ( 4a - b +9c ) and ( - 2b + 3c - a).
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Answer:
Sum = a+3b-4c+4a-b+9c+(-2b)+3c-a
= 4a-8c
Difference = 4a-8c-(2a-3b+4c)
= 4a-8c-2a+3b- 4c
= 2a+3b-12c
Hope it helps you
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