Question

Subtract (2a-3b+4c) from the sum of (a+3b-4c),(4a-b+9c) and (-2b+3c-a)
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Answer 1

Sum of the numbers (a + 3b - 4c) , (4a - b + 9c) , (-2b + 3c -a) is (4a + 8c)

Now subtract ( 2a -3b + 4c ) from the sum

( 4a + 8c) - ( 2a -3b + 4c ) = (2a + 4c + 3c)

Answer 2

Answer:

2a+3b+4c

Step-by-step explanation:

(a+3b-4c )+(4a-b+9c)+( -2b+3c-a)

=4a-2b+2b+8c

=4a+8c

now Subtract (2a-3b+4c) from 4a+8c

so,

4a+8c -(2a-3b+4c)

=4a+8c-2a+3b-4c

=2a+3b+4c #######

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