subtract (2a-3b+4c)from the sum of (a+3b-4c),(4a-b+9c)and (-2b+3c-a)
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here is your answer mate......
....
=>(a+3b-4c)+(4a-b+9c)+(-2b+3c-a)-(2a-3b+4c)
=a+4a-a-2a+3b-b-2b+3b-4c+9c+3c-4c
=2a+3b+12c
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