Question

Subtract (2a-3b+4c) from the sum
of (a+3b-4c), (4a-b+9c) and (-2b+3c-a)​

Answer 1

Step-by-step explanation:

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).

So, First we will do the sum of the three given polynomials,

Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)

=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)

=4a+8c

Now, we can perform the subtraction,

∴ Required difference

=(4a+8c)−(2a−3b+4c)

=4a+8c−2a+3b−4c

=2a+3b+4c

Answer 2

Step-by-step explanation:

= ( a + 3b-4c)+(4a-b+9c)+(-2b+3c-a)-(2a-3b+4c)

= a+3b-4c+4a-b+9c-2b+3c-a-2a+3b-4c

= 2a+3b+4c

The answer is 2a+3b+4c.

I hope it will help you .