Question

subtract (2a+3b +4c) from the sum of (a-3b-4c) (4a -b-9c) and (2b+3c+a)​

Answer 1

Step-by-step explanation:

$(2a + 3b + 4c \: from \: (a - 3b - 4c) \: (4a - b - 9c) \: (2b + 3c + a)$

$(a - 3b - 4c) \: (4a - b - 9c) \: (2b + 3c + a) \: \: - \: \: (2a + 3b + 4c)$

$a - 4a - a \: \: \: - \: \: \: 3b - b - 2b - 3b \: \: \: \: \: - \: \: \: 4c - 9c - 3c - 4c$

$( - 4a) \: \: - \: \: ( - 3b) \: \: - \: \: ( - 12c)$

$is \: your \: right \: answer$