Question

Subtract (2a - 3b + 4c) from the sum of (a + 3b-4c). (4a - b +9c) and (-2b +3c-a). from the sum of 2m + 4n-3​

Answer 1

Answer:

it is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).

So,

First we will do the sum of the three given polynomials,

Sum = (a+3b−4c) + (4a−b+9c) + (−2b+3c−a)

= (a+4a−a) + (3b−b−2b) + (−4c+9c+3c)

= 4a + 8c

Now, we can perform the subtraction,

∴ Required difference

= (4a+8c) − (2a−3b+4c)

= 4a+8c − 2a+3b−4c

$\pink{\textsf{= 2a + 3b + 4c}}$

Answer 2

$So, \: the \: answer \: will \: be \: 2a+3b+4c.$