subtract ( 2a-3b+4c) from the sum of ( a+3b-4c),(4a-b+9c)and (-2b+3c-a)
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add firstly the three given relations and then subtracy 2a-3b+4c from this
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Answer:
2a+3b+4c
Step-by-step explanation:
{( a+3b-4c)+(4a-b+9c) + (-2b+3c-a)}-( 2a-3b+4c)
{a+3b-4c+4a-b+9c -2b+3c-a}-( 2a-3b+4c)
(4a+0b+8c)-(2a-3b+4c)
4a+0b+8c-2a+3b-4c
2a+3b+4c
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