subtract (2a-3b+4c) from the sum of (a+3b-4c),(4a-b+9c) and (-2b+3c-9)
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brunoconti:
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Sum of (a+3b-4c) + (4a-b+4c) + (-2b+3c-9) = a + 3b - 4c + 4a - b + 4c - 2b + 3c - 9 = 5a + 3c - 9
Subtraction of (2a-3b+4c) from (5a+3c-9) = 5a + 3c - 9 - 2a + 3b - 4c = 3a + 3b - c - 9.
Therefore, the answer is 3a + 3b - c - 9.
Subtraction of (2a-3b+4c) from (5a+3c-9) = 5a + 3c - 9 - 2a + 3b - 4c = 3a + 3b - c - 9.
Therefore, the answer is 3a + 3b - c - 9.
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