subtract (2a_3b +4c)from the sum of (a+3b_4c), (4a_b+ac)and (_2b+3c_c).
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(a+3b-4c)+(4a-b+ac)+(-2b+3c)=5a+b-c+ac)
then subtract (5a+b-c+ac)-(2a-3b+4c)=3a+4b - 5c+ac
then subtract (5a+b-c+ac)-(2a-3b+4c)=3a+4b - 5c+ac
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