Math, asked by anshubhuvns123, 4 months ago

Subtract (2a-3b+4c) from the sum of (a+3b-4c) and (4a-b+9c). *

3 points

(3a+5b+2c)

(3a+5b+c)

(3a+2b+5c)

(5a+3b-c)

Answers

Answered by shreya2703
1

Answer:

(3a+5b+c)

Step-by-step explanation:

First take the sum of (a+3b-4c) and (4a-b+9c)

(a+3b-4c)+(4a-b+9c)

a+3b-4c+4a-b+9c

a+4a+3b-b-4c+9c (rearranging the terms together)

5a+2b+5c (sum of the two terms)

now,

according to the question subtract (2a-3b+4c) from the sum of (a+3b-4c) and (4a-b+9c) which is 5a+2b+5c.

(5a+2b+5c)-(2a-3b+4c)

5a+2b+5c-2a+3b-4c

Ans:-(3a+5b+c)

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