Subtract (2a-3b+4c) from the sum of (a+3b-4c) and (4a-b+9c). *
3 points
(3a+5b+2c)
(3a+5b+c)
(3a+2b+5c)
(5a+3b-c)
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Answer:
(3a+5b+c)
Step-by-step explanation:
First take the sum of (a+3b-4c) and (4a-b+9c)
(a+3b-4c)+(4a-b+9c)
a+3b-4c+4a-b+9c
a+4a+3b-b-4c+9c (rearranging the terms together)
5a+2b+5c (sum of the two terms)
now,
according to the question subtract (2a-3b+4c) from the sum of (a+3b-4c) and (4a-b+9c) which is 5a+2b+5c.
(5a+2b+5c)-(2a-3b+4c)
5a+2b+5c-2a+3b-4c
Ans:-(3a+5b+c)
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