subtract (2a- 3b+4c) from the sum of (a+ 3b -4c ) and (-9a-4c)
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Solution:-
the sum of (a+3b-4c) and (-9a-4c)=(a+(-9a))+(3b)+(-4c+(-4c))
=-8a+3b-8c
now,
subtracting (2a-3b+4c) from (-8a+3b-8c)
=(-8a+3b-8c)-(2a-3b+4c)
=(-8a+3b-8c-2a+3b-4c)
=-10a+6b-12c
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