subtract 2a+5b+2c-9 from 3a-4b-c+6
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Answered by
2
Answer:
We have to subtract 2a−5b+2c−9 from 3a−4b−c+6
So, simply numeric coefficients of same varaibles will be subtracted.
∴(3a−4b−c+6)−(2a−5b+2c−9)
=(3−2)a+(−4−(−5))b+(−1−2)c+(6−(9))
=a+b−3c+15
Step-by-step explanation:
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Answered by
0
=>(3a-4b-c+6)-(2a+5b+2c-9)
=>3a-4b-c+6-2a-5b-2c+9
=>a-9b-3c+15
Thus , when we subtract 2a+5b+2c-9 from 3a-4b-c+6
we get a-9b-3c+15
HOPE THIS WILL HELP YOU
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