Math, asked by chrisvlogs90, 8 months ago

subtract 2a²-ab-3b²+bc+ac from 2ac-3bc+4ac-a²-3b² . please find the correct answer with solution​

Answers

Answered by amitadasdgp6
0

Answer:

Answer:5ac-4bc-3a²+ab

Answer:5ac-4bc-3a²+abStep-by-step explanation:

Answer:5ac-4bc-3a²+abStep-by-step explanation:

Answer:5ac-4bc-3a²+abStep-by-step explanation: 2ac-3bc+4ac-a²-3b² - (2a²-ab-3b²+bc+ac)

Answer:5ac-4bc-3a²+abStep-by-step explanation: 2ac-3bc+4ac-a²-3b² - (2a²-ab-3b²+bc+ac)= 2ac-3bc+4ac-a²-3b² -2a²+ab+3b²-bc-ac

Answer:5ac-4bc-3a²+abStep-by-step explanation: 2ac-3bc+4ac-a²-3b² - (2a²-ab-3b²+bc+ac)= 2ac-3bc+4ac-a²-3b² -2a²+ab+3b²-bc-ac= 2ac+4ac-ac-3bc-bc-3b²+3b²-2a²-a²+ab

Answer:5ac-4bc-3a²+abStep-by-step explanation: 2ac-3bc+4ac-a²-3b² - (2a²-ab-3b²+bc+ac)= 2ac-3bc+4ac-a²-3b² -2a²+ab+3b²-bc-ac= 2ac+4ac-ac-3bc-bc-3b²+3b²-2a²-a²+ab= 6ac-ac-4bc-3a²+ab

Answer:5ac-4bc-3a²+abStep-by-step explanation: 2ac-3bc+4ac-a²-3b² - (2a²-ab-3b²+bc+ac)= 2ac-3bc+4ac-a²-3b² -2a²+ab+3b²-bc-ac= 2ac+4ac-ac-3bc-bc-3b²+3b²-2a²-a²+ab= 6ac-ac-4bc-3a²+ab= 5ac-4bc-3a²+ab

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