Question

subtract -2a2+b2-ab+a from the sum of : a2-b2+2ab,a2+4b2-6ab,b2+6,a2-4ab and-2a2+b2-ab+a.​

Answer 1

Answer:

The factors of `8a^3+b^3-6a b+1` are (a) `(2a+b-1)(4a^2+b^2+1-3a b-2a)` (b)`(2a-b+1)(4a^2+b^2-4a b+1-2a+b)` (c)`(2a+b+1)(4a^2+b^2+1-2a b-b-2a)` (d)`(2a-1+b)(4a^2+1-4a-b-2a b)`