Question

subtract 2k(4k-l+3m) from 4k (2k+l-2m)​

Answer 1

2k (4k-l+3m) = 8k^2 -2kl +6km

4k (2k+l-2m) = 8k^2 +4kl -8km

2k (4k-l+3m)-4k (2k+l-2m)

= 8k^2 -2kl +6km -(8k^2+4kl-8km)

= -2kl -4kl +6km+8km

= -6kl +14km

= 14km- 6kl

= 2k (7m-3l)

Answer 2

Step-by-step explanation:

[4k(2k+l-2m)] - [2k(4k-l+3m)]

=8k^2+4k.l-8k.m-8k^2+2k.l-6k.m

=4k.l-8k.m+2k.l-6k.m

=6k.l-14k.m

=2k[3l-7m].