Math, asked by kaushikikashyap557, 2 days ago

subtract (2x - 3y + 4z) from the sum of (x + 3y - 4z), (4x - y + 9z) and (-2x + 3y - z).​

Answers

Answered by sanuroy99236
0

Step-by-step explanation:

( 2x - 3y + 4z ) - ( x+3y- 4z )

= 2x- 3y + 4z - x - 3y + 4z = 0

= 2x - x - 3y - 3y + 4z + 4z = 0

= X -- 6y + 8z = 0 ------------- Equation (1)

(4x - y + 9z ) - ( -2x + 3y - z ) = 0

= 4x - y + 9z + 2x - 3y + z = 0

= 4x + 2x - y - 3y + 9z + z = 0

= 6x - 4y + 10z = 0 ---------------- Equation (2)

Equation (1) & ( 2) solving (add)

(X - 6y + 8z ) + ( 6x - 4y + 10z ) = 0

= X - 6y + 8z + 6x - 4y + 10z = 0

= X + 6x - 6y - 4y + 8z + 10z = 0

= 7x - 10y + 18z = 0 ( Answer)

Explanation : l hope it is helpful ..........

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