Subtract 2x (z−x−y) from 2y (z−y−x)
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Answer:
(2y(z-y-x) )- (2x(z-x-y))
=( 2yz-2y^2-2yx)-( 2xz-2x^2-2xy)
= ( 2yz- 2y^2-2yx-2xz+2x^2+2xy)
=(2yz-2y^2-2xz+2x^2)
= ( 2x^2-2y^2-2xz+2yz)
= 2(x^2-y^2) - 2z(x-y) [ final expression]
Step-by-step explanation:
hope it helps you
Answered by
3
Answer:
2z( y - x ) - 2 ( y^2 - x ^2 )
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