Question

subtract:2x²-3y²from3x²+2y²​

Answer 1

Answer:

2x²-3y²-(3x²+2y²)

2x²-3y²-3x²-2y²

-x2-5y²

Answer 2

Answer:

$=3x^2+2y^2-(2x^2-3y^2)=x^2+5y^2$

Step-by-step explanation:

Given : Equation $2x^2-3y^2$ and $3x^2+2y^2$

To find : Subtract $2x^2-3y^2$ from $3x^2+2y^2$ ?

Solution :

Step 1 - Write the equations,

$2x^2-3y^2$ and $3x^2+2y^2$

Step 2 - Subtract 1 equation from 2,

$=3x^2+2y^2-(2x^2-3y^2)$

Step 3 - Solve,

$=3x^2+2y^2-2x^2+3y^2$

$=x^2(3-2)+y^2(2+3)$

$=x^2+5y^2$

Therefore, $=3x^2+2y^2-(2x^2-3y^2)=x^2+5y^2$