Question

Subtract 2x3+x2+4x-6 from x3+ 5x2-4x+6
Please answer​

Answer 1

Answer:

-x3+4x2-8x+12

Step-by-step explanation:

x3+ 5x2-4x+6 - (2x3+x2+4x-6)

= x3+ 5x2-4x+6 - 2x3-x2-4x+6

= x3- 2x3+ 5x2-x2-4x-4x+6+6

= -x3+4x2-8x+12

Hope this helps

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Answer 2

Subtraction

Step-by-step explanation:

Value 1 is 2$x^{3}$ + $x^{2}$ + 4x - 6

Value 2  is $x^{3}$ + 5$x^{2}$ - 4x + 6

Now we have to subtract the value one from value 2.

( $x^{3}$ + 5$x^{2}$ - 4x + 6) - (2$x^{3}$ + $x^{2}$ + 4x - 6)

Opening the braces, it will change the sign of the values.

=  $x^{3}$ + 5$x^{2}$ - 4x + 6 + 2$x^{3}$ - $x^{2}$ - 4x + 6

= 3$x^{3}$ + 5$x^{2}$ - 4x + 6 - $x^{2}$ - 4x + 6

= 3$x^{3}$ + 4$x^{2}$ - 4x + 6 - 4x + 6

= 3$x^{3}$ + 4$x^{2}$ - 8x + 6 + 6

= 3$x^{3}$ + 4$x^{2}$ - 8x + 12

So, if we subtract  2$x^{3}$ + $x^{2}$ + 4x - 6 from  $x^{3}$ + 5$x^{2}$ - 4x + 6, we will get 3$x^{3}$ + 4$x^{2}$ - 8x + 12.