Subtract 2xy-3yz+5xz from 16xy+7yz-14zx
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Answer:
Subtracting,
7xy(x
2
−2xy+3y
2
)−8x(x
2
y−4xy+7xy
2
) from 3y(4x
2
y−5xy+8xy
2
)
⇒ 7x
3
y−14x
2
y
2
+21xy
3
−8x
3
y+32x
2
y−56x
2
y
2
from 12x
2
y
2
−15xy
2
+24xy
3
= (12x
2
y
2
−15xy
2
+24xy
3
)−(7x
3
y−14x
2
y
2
+21xy
3
−8x
3
y+32x
2
y−56x
2
y
2
= 12x
2
y
2
−15xy
2
+24xy
3
−7x
3
y+14x
2
y
2
−12xy
3
+8x
3
y−32x
2
y+56x
2
y
x
2
= 82x
2
y
2
+3xy
3
+x
3
y−15xy
2
−32x
2
y
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Step-by-step explanation:
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